Talk:Aufgaben:Problem 6

In my view, the statement \(Ker(A) \neq 0\) must be a typo in the textbook. I corrected it to \(Ker(A - \lambda 1)\neq 0\)

--Brynerm (talk) 22:36, 29 June 2015 (CEST)

The "alternative" solution has one typo in b) as \(\rho(g)\) is meant to be unitary (not self-adjoint), therefore there must be an \(\rho(g)^{-1}=\rho(g^{-1})\) in the equation with the scalar product. Apart from that, it's really all the same but more detailed and therefore it might be easier to follow.

--Brynerm (talk) 09:15, 30 June 2015 (CEST)

Thank you so much for noticing. I'll fix it tomorrow morning. I'll also add a source file, so everyone can edit it. Actually, that's a major mistake which could cost many points at the exam.

--Lilit (talk) 12:43, 30 June 2015 (CEST)