Difference between revisions of "Talk:Aufgaben:Problem 6"
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--[[User:Brynerm|Brynerm]] ([[User talk:Brynerm|talk]]) 09:15, 30 June 2015 (CEST) | --[[User:Brynerm|Brynerm]] ([[User talk:Brynerm|talk]]) 09:15, 30 June 2015 (CEST) | ||
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+ | Thank you so much for noticing. I'll fix it tomorrow morning. I'll also add a source file, so everyone can edit it. Actually, that's a major mistake which could cost many points at the exam. | ||
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+ | --[[User:Lilit|Lilit]] ([[User talk:Lilit|talk]]) 12:43, 30 June 2015 (CEST) |
Revision as of 10:43, 30 June 2015
In my view, the statement \(Ker(A) \neq 0\) must be a typo in the textbook. I corrected it to \(Ker(A - \lambda 1)\neq 0\)
--Brynerm (talk) 22:36, 29 June 2015 (CEST)
The "alternative" solution has one typo in b) as \(\rho(g)\) is meant to be unitary (not self-adjoint), therefore there must be an \(\rho(g)^{-1}=\rho(g^{-1})\) in the equation with the scalar product. Apart from that, it's really all the same but more detailed and therefore it might be easier to follow.
--Brynerm (talk) 09:15, 30 June 2015 (CEST)
Thank you so much for noticing. I'll fix it tomorrow morning. I'll also add a source file, so everyone can edit it. Actually, that's a major mistake which could cost many points at the exam.